Tính y" của hàm số: $y=sinx.e^{2x}.sinx$
Edited by phanquockhanh, 22-07-2013 - 20:51.
#2
Posted 22-07-2013 - 18:38
bangbang1412
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- Phó Quản lý Toán Cao cấp
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Độc cô cầu bại
$y=sin^{2}x.e^{x}$
$y'=(sin^{2}x)'.e^{x}+(e^{x})'.sin^{2}x$ =>$ y'= sin2x.e^{x}+e^{x}.sin^{2}x $
$y'' = (y')'=cos2x.e^{x}+e^{x}.sin2x$
Edited by phanquockhanh, 22-07-2013 - 20:51.
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