1) $3\sqrt{5-x}+3\sqrt{x-4}=2x-7$.
2)$\sqrt{x^{2}+3}+\sqrt{2x-1}=3$
1) $3\sqrt{5-x}+3\sqrt{x-4}=2x-7$.
2)$\sqrt{x^{2}+3}+\sqrt{2x-1}=3$
2) pt trở thành: $\sqrt{x^{2}+3}-2+\sqrt{2x-1}-1=0\Leftrightarrow \frac{x^{2}-1}{\sqrt{x^{2}+3}+2}+\frac{2x-2}{\sqrt{2x-1}+1}=0\Leftrightarrow (x-1)(\frac{x+1}{\sqrt{x^{2}+3}+2}+\frac{2}{\sqrt{2x-1}+1})=0\Leftrightarrow x=1$
"Life would be tragic if it weren't funny"
-Stephen Hawking-
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