$$\sqrt{\frac{a}{4a+4b+c}}+\sqrt{\frac{b}{4b+4c+a}}+\sqrt{\frac{c}{4c+4a+b}} \le 1$$
(Phạm Kim Hùng)
15-08-2012 - 23:01
(Phạm Kim Hùng)
03-08-2012 - 19:13
21-07-2012 - 13:18
07-07-2012 - 13:45
06-07-2012 - 19:22
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