a) $\sqrt[4]{17-x^{8}}-\sqrt[3]{2x^{8}-1}=1$
b) $x+\sqrt{4-x^{2}}=2+3x\sqrt{4-x^{2}}$
c)$2x^{2}+\sqrt{1-x}+2x\sqrt{1-x^{2}}=1$
d)$\sqrt[3]{81x-8}=x^{3}-2x^{2}+\frac{4}{3}x-2$
e)$\sqrt[3]{3x+4}=x^{3}+3x^{2}+x-2$
f)$\sqrt[3]{x^{2}-2}=\sqrt{2-x^{3}}$