1) $4\sqrt{x^2+x+1}=1+5x+4x^2-2x^3-x^4$
2) $\sqrt{x(x-1)}+\sqrt{x(x+2)}=2\sqrt{x^2}$
3) $\sqrt{x+3}+2x\sqrt{x+1}=2x+\sqrt{x^2+4x+3}$
4) $729x^4+8\sqrt{1-x^2}=36$
5) $\sqrt{x^2-8x+15}+\sqrt{x^2+2x-15}=\sqrt{x^2-9x+18}$
6) $4x^2+\sqrt{2x+3}=8x+1$
7) $\sqrt{2x^2+8x+6}+\sqrt{x^2-1}=2x+2$
8) $2x^2-6x+10-5(x-2)\sqrt{x+1}=0$
9) $\sqrt{x^2+10x+21}=3\sqrt{x+3}+2\sqrt{x+7}-6$
10) $\sqrt{x^2-x-2}-2\sqrt{x-2}+2=\sqrt{x+1}$
11) $x-2\sqrt{x-1}-(x-1)\sqrt{x}+\sqrt{x^2-x}=0$
12) $\sqrt[3]{x+1}+\sqrt[3]{x+2}=1+\sqrt[3]{x^2+3x+2}$
13) $\sqrt{x}+\sqrt{x+1}-\sqrt{x^2+x}=1$
14) $\sqrt{x+1}+2(x+1)=x-1+\sqrt{1-x}+3\sqrt{1-x^2}$
15) $x+2\sqrt{7-x}=2\sqrt{x-1}+\sqrt{-x^2+8x-7}+1$
16) $\sqrt[3]{x+1}+\sqrt[3]{x^2}=\sqrt[3]{x}+\sqrt[3]{x^2+x}$
17) $(x+3)\sqrt{10-x^2}=x^2-x-12$
18) $\dfrac{x^2}{\sqrt{3x-2}}-\sqrt{3x-2}=1-x$
19) $3x^2+3x+2=(x+6)\sqrt{3x^2-2x-3}$
20) $x^2+x+2=(3x-2)\sqrt{x+1}$
Bài viết đã được chỉnh sửa nội dung bởi cityhuntervp: 05-11-2013 - 15:56