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Tìm giới hạn: $lim\frac{\sqrt{n^2+2n+4}+(3\sqrt{n}+1)(2\sqrt{n}+1)}{(\sqrt{n}-1)(2\sqrt{n}+3)+\sqrt{4n^2+n+1}}$

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#1
snowangel1103

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Tìm giới hạn dãy số

$1/ lim\frac{\sqrt{n^2+2n+4}+(3\sqrt{n}+1)(2\sqrt{n}+1)}{(\sqrt{n}-1)(2\sqrt{n}+3)+\sqrt{4n^2+n+1}}$
 
$2/ lim\frac{\sqrt{4n^2+3n+1}+n+2}{2n-3+\sqrt{n^2+1}}$

 



#2
tienvuviet

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$\lim \dfrac{\sqrt{1+\dfrac{2}{n}+\dfrac{4}{n^2}}+(3+\dfrac{1}{\sqrt n})(2+\dfrac{1}{\sqrt n})}{(1-\dfrac{1}{\sqrt n})(2+\dfrac{3}{\sqrt n})+\sqrt{4+\dfrac{1}{n}+\dfrac{1}{n^2}}}=\dfrac{7}{4}$


Edited by tienvuviet, 19-01-2014 - 12:21.


#3
tienvuviet

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$\lim \dfrac{\sqrt{4+\dfrac{3}{n}+\dfrac{1}{n^2}}+1+\dfrac{2}{n}}{2-\dfrac{3}{n} +\sqrt{1+\dfrac{1}{n^2}}}=1$






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