Cho $a,b,c>0$ thoả mãn:$ab+bc+ca=\frac{1}{3}$.Tim Max $P=\sum \frac{1}{a^2-bc+1}$
Edited by Mikhail Leptchinski, 15-11-2014 - 22:48.
Cho $a,b,c>0$ thoả mãn:$ab+bc+ca=\frac{1}{3}$.Tim Max $P=\sum \frac{1}{a^2-bc+1}$
Edited by Mikhail Leptchinski, 15-11-2014 - 22:48.
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