Cho tam giác ABC,chứng minh:
$S\leq \frac{p^2}{3\sqrt{3}}$
Edited by Mikhail Leptchinski, 23-11-2014 - 22:37.
$S\leq \frac{p^2}{3\sqrt{3}}$
Started By nxhoang99, 23-11-2014 - 16:01
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