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$\left\{\begin{matrix} & \frac{1}{\sqrt{x+2}}+\frac{1}{\sqrt{y-1}}=\frac{2}{\sqrt{x+y}}\\ & x^2+y^2+4xy-4x+2y-5=0 \end{matrix}\right.$

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tritanngo99

tritanngo99

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Giải hệ phương trình: $\left\{\begin{matrix} & \frac{1}{\sqrt{x+2}}+\frac{1}{\sqrt{y-1}}=\frac{2}{\sqrt{x+y}}\\ & x^2+y^2+4xy-4x+2y-5=0 \end{matrix}\right.$







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