Cho X=$\frac{a+b}{c}$=$\frac{b+c}{a}$=$\frac{c+a}{b}$.Tính A=$(X^{2}-X+1)^{10}$
Edited by tungpro1z4, 30-09-2016 - 18:36.
Cho X=$\frac{a+b}{c}$=$\frac{b+c}{a}$=$\frac{c+a}{b}$.Tính A=$(X^{2}-X+1)^{10}$
Edited by tungpro1z4, 30-09-2016 - 18:36.
๖Tùng☼Pro๖
Cho X=$\frac{a+b}{c}$=$\frac{b+c}{a}$=$\frac{c+a}{b}$.Tính A=$(X^{2}-X+1)^{10}$
ta dễ dàng tìm được a=b=c => x=2
thay vào ta được A=59049($3^{10}$)
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