Giải hệ phương trình:
$\left\{\begin{matrix}2x^{2}+2x+y^{2}+y=6 \\xy(xy+x+y+1)=4 \end{matrix}\right.$
Edited by trieuduc0101, 09-10-2016 - 08:38.
GHPT: $\left\{\begin{matrix}2x^{2}+2x+y^{2}+2=6 \\xy(xy+x+y+1)=4 \end{matrix}\right.$
Started By trieuduc0101, 06-10-2016 - 21:09
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