$1) \large \sqrt{17+5 \sqrt{4x^{2}-16} } +x^{2} \sqrt{7-x}=3$
$2) \large \sqrt{x+1}+ \sqrt{x+ \sqrt{2} } =2$
$3) \large \dfrac{2x-8}{ \sqrt{6-x} } + \sqrt{6-x} =3 \sqrt{x-4} $
$4) \large \sqrt[3]{25+ \sqrt{x^{2}+3} }=3$
$5) \large \sqrt{5- \sqrt{x+1+ \sqrt{2x^{2}+x+3} } } =1$
$6) \large x \sqrt{36x+1261} =18x^{2}-17x $
$7) \large \sqrt{ \dfrac{1+2x \sqrt{1-x^{2}} }{2} } +2x^{2}=1$
$8) \large \left\{\begin{matrix}x^{3}- \sqrt{y}=1\\ 5x^{6}+2y-8x^{3} \sqrt{y} =2 \end{matrix}\right.$
$9) \large \left\{\begin{matrix}(3x+y)^{x-y} =9\\ \sqrt[x-y]{324} =18x^{2}+12xy+2y^{2} \end{matrix}\right.$
$10) \large 2x+7= \sqrt[4]{4x-3} +4 \sqrt{x+3} $
$11) \large \sqrt{x^{2}+1}=x^{2}+x+ \sqrt{2x^{2}+x+1} $
$12) \large (x^{2}+3x)-(2x+4) \sqrt{x^{2}+3x} +8x=0$
$13) \large \sqrt{2x^{2}+x+6}+ \sqrt{x^{2}+x+6}=x+ \dfrac{4}{x} $
$14) \large \sqrt{x} + \sqrt[3]{x+7}= \sqrt[4]{x+80} $
$15) \large x^{3}-3x^{2}-8x+40-8 \sqrt[4]{4x+4} =0$
Bài viết đã được chỉnh sửa nội dung bởi xusinst: 17-05-2012 - 01:29
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