Giải phương trình:
a/ $\frac{8}{sin^{3}2x}+cotx=tan^{3}x$
b/ $cos2x-3sin2x+5\sqrt{2}(x+\frac{9\pi }{4})=3$
c/ $sin^{3}x+cos^{3}x-\sqrt{3}sin2x(sinx-cosx)=sinxcosx(sinx+cosx)$
d/ $\sqrt{3}cos2x(2sinx-1)+2cosx(2sin^{2}x+1)=3sin2x$
e/ $\frac{1}{cosx}-\frac{cos^{2}4x}{sin2x}=sin2x+sin6x$
