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$2(1+abc)+\sqrt{2(1+a^{2})(1+b^{2})(1+c^{2})}\geq (1+a) (1+b) (1+c)$


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hieu31320001

hieu31320001

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Cho a,b,c là các số thực. CM:

$2(1+abc)+\sqrt{2(1+a^{2})(1+b^{2})(1+c^{2})}\geq (1+a) (1+b) (1+c)$


Knowing both victory and defeat.That is the way you become a real man-Shanks





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