Có nghiệm : $\sqrt{y + 3} + \sqrt{y + 1} = m( 1 + \sqrt{3-y})$
Vô nghiệm : $x^2 - 4 |x - 1| < m$
#1
Posted 03-12-2017 - 10:45
Silverbullet069
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Thiếu úy
"I am the bone of my sword,
Unknown to Death, Nor known to Life,
So as I pray, unlimited blade works."
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