Giải hệ phương trình:$\left\{\begin{matrix}x^2y^2-xy-3y^2=-1\\ x^3y^3-x^2y^3+2xy^2-2xy^3-5y^2=-1\\ \end{matrix}\right.$
$\left\{\begin{matrix}x^2y^2-xy-3y^2=-1\\ x^3y^3-x^2y^3+2xy^2-2xy^3-5y^2=-1\\ \end{matrix}\right.$
Started By melodias2002, 02-03-2018 - 00:14
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