Giải hệ phương trình
$\left\{\begin{matrix} x^3-x^2+x+y-2=0 & \\ y^3-y^2+y+2z-3=0 & \\ z^3-z^2+z+3x-4=0 & \end{matrix}\right.$
Giải hệ phương trình
$\left\{\begin{matrix} x^3-x^2+x+y-2=0 & \\ y^3-y^2+y+2z-3=0 & \\ z^3-z^2+z+3x-4=0 & \end{matrix}\right.$
$\left\{\begin{matrix}x^{3}-x^{2}+x-1=1-y \\ y^{3}-y^{2}+y-1=2(1-z) \\ z^{3}-z^{2}+z-1=3(1-x) \end{matrix}\right. <=>\left\{\begin{matrix}(x-1)(x^{2}+1)=1-y \\ (y-1)(y^{2}+1)=2(1-z) \\ (z-1)(z^{2}+1)=3(1-x) \end{matrix}\right. =>(x-1)(y-1)(z-1)((x^{2}+1)(y^{2}+1)(z^{2}+1)+6)=0<=> \begin{bmatrix}x=1 \\ y=1 \\ z=1 \end{bmatrix}$
Treasure every moment that you have!
And remember that Time waits for no one.
Yesterday is history. Tomorrow is a mystery.
Today is a gift. That’s why it’s called the present.
Theo bạn thì PT còn nghiệm nào nữa không ?
Leonhard Euler [15/4/1707 - 18/9/1783]
----- Never give up -----
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