Chứng minh phương trình sau luôn có 2 nghiệm ($\alpha_{1}>\alpha_{2}>\alpha_{3}$ và a, b, c < 0)
$\frac{a}{\sqrt[3]{1-x}-\alpha_{1}}+\frac{b}{\sqrt[3]{1-x}-\alpha_{2}}+\frac{c}{\sqrt[3]{1-x}-\alpha_{3}}=0$
$\frac{a}{\sqrt[3]{1-x}-\alpha_{1}}+\frac{b}{\sqrt[3]{1-x}-\alpha_{2}}+\frac{c}{\sqrt[3]{1-x}-\alpha_{3}}=0$
Started By beanhdao01, 25-04-2018 - 00:09
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