$1, x,y,z>0, Max:P=\frac{xyz(x+y+z+\sqrt{x^{2}+y^{2}+z^{2}})}{(x^{2}+y^{2}+z^{2})(xy+xz+yz)}$
$2,0\leq a,b,c\leq 1, a+b+c=1, Min,Max: P=\sqrt{a+b}+\sqrt{b+c}+\sqrt{c+a}$
$3,Cho:0\leq a,b,c\leq 4, a+b+c=6, MAX:P=a^{2}+b^{2}+c^{2}+ab+ac+bc$
$4, a,b,c>0, a+2b+3c\geq 10, CMR: a+b+c+\frac{3}{4a}+\frac{9}{8a}+\frac{1}{c}\geq \frac{13}{2}$
$5,a,b,c>0, ab+ac+bc+abc\leq 4,CMR: $a^{2}+b^{2}+c^{2}+a+b+c\geq 2(ab+ac+bc)$
$6,Cho a,b,c>0, a+b+c=1, MAX:P=\sum \frac{a}{9a^{3}+3b^{2}+c}$
$7,a,b,c>0, a+b+c=3:Min:P=\sum a^{2}+\frac{ab+ac+bc}{a^{2}b+b^{2}c+c^{2}a}$
$8,x,y,z>0, x+y+z=18\sqrt{2}, CMR:P=\sum \frac{1}{\sqrt{x(y+z)}}\geq \frac{1}{4}$
Bài viết đã được chỉnh sửa nội dung bởi Le Hoang Anh Tuan: 29-05-2018 - 14:42