Chủ đề này có 1 trả lời

[Chickey]

$\left\{\begin{matrix} (2x-1)\sqrt{x+y}=(6-x-y)\sqrt{2-x} & \\ x^{2}+11x+y=4+\sqrt{6x+y} & \end{matrix}\right.$

[PugMath]

$-2(2-x)\sqrt{x+y}+3\sqrt{x+y}=6\sqrt{2-x}-(x+y)\sqrt{2-x}<=>\sqrt{(2-x)(x+y)}(2\sqrt{2-x}-\sqrt{x+y})+3(2\sqrt{2-x}-\sqrt{x+y})=0=>2\sqrt{2-x}=\sqrt{x+y}=>8-4x=x+y<=>y=8-5x$

=> $x^2+11x+8-5x=4+\sqrt{6x+8-5x}<=>x^2+6x+4=\sqrt{x+8}<=>(x^2+5x+1)(x^2+7x+8)=0=>.........$