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Tìm m để pt sau có 3 nghiệm x1 < x2 <x3 sao cho x1+x3=2x2
$x^3-(m+6)x^2+(6m+8)x-8m=0$
Tìm m để pt sau có 3 nghiệm x1 < x2 <x3 sao cho x1+x3=2x2 $x^3-(m+6)x^2+(6m+8)x-8m=0$
$x(x^2-6x+8)-m(x^2-6x+8)=0<=> (x-m)(x^2-6x+8)=0$
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