Chủ đề này có 1 trả lời

[DOTOANNANG]

$a\geqq b\geqq 0,\,3\,a+ 2\,b- 6= ac+ 4\,b- 8= 0$

$$\therefore\,\min c,\,\max c= \it{?}$$

[DOTOANNANG]

$$\because\,a(\,3\,c- 8\,)+ 3\,a(\,4- c\,)= 4\,a\geqq 0$$

v à

$$\because\,3\,a^{\,2}(\,3\,c- 8\,)(\,4- c\,)= 16\,b(\,a- b\,)\geqq 0$$