xét tính hội tụ, phân kì của dãy số sau
$\sum_{n=1}^{\infty } \frac{n^{n+\frac{1}{n}}}{(n+\frac{1}{n})^{n}}$
$\sum_{n=2}^{\infty } \frac{1}{log(n)^{log(n)}}$
$\sum_{n=1}^{\infty } \frac{n^{n+\frac{1}{n}}}{(n+\frac{1}{n})^{n}}$
Started By Minato, 01-12-2021 - 20:53
#1
Posted 01-12-2021 - 20:53
Minato
-
- Thành viên
-
- 179 posts
Trung sĩ
Life has no meaning, but your death shall
1 user(s) are reading this topic
0 members, 1 guests, 0 anonymous users
