Cho các số thực $a_{1},a_{2},...,a_{n} \geq 0$ và $\frac{1}{a_{1}+1}+\frac{1}{a_{2}+1}+...+\frac{1}{a_{n}+1} = n-1$.
Chứng minh rằng:
$a_{1}a_{2}...a_{n}\leq \frac{1}{(n-1)^n}$
$a_{1}a_{2}...a_{n}\leq \frac{1}{(n-1)^n}$
Started By bimcaucau, 29-03-2022 - 16:57
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