$ \left\{\begin{array}{l}x-y-z=-3 \\x^2-y^2-z^2=1\end{array}\right. $
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P/S: Bạn chú ý cách đặt tiêu đề bài viết.
Edited by binhmetric, 16-07-2012 - 13:16.
Edited by binhmetric, 16-07-2012 - 13:16.
$\left\{\begin{array}{l}x-y-z=-3 (1) \\x^2-y^2-z^2=1(2)\end{array}\right.$Giải hệ phương trình nghiệm nguyên:
$ \left\{\begin{array}{l}x-y-z=-3 \\x^2-y^2-z^2=1\end{array}\right. $
Edited by henry0905, 15-07-2012 - 18:22.
Edited by defaw, 15-07-2012 - 18:43.
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