$x+2y$$/ x^2+y^2$=7/20
$(1+xy)(1+yz)(1+xz)=xyzt$
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Posted 22-08-2010 - 06:35
pham quang thang
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$x+2y$$/ x^2+y^2$=7/20
$(1+xy)(1+yz)(1+xz)=xyzt$
ban xem lai de cau 2 di no phai la =8xyz
neu=8xyz thi ban su dung bdt Co-si sau do xet dieu kien xay ra dau =
x= y= z=1
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