$\left\{\begin{matrix}4xy + 4({x^2} + {y^2})+\frac{3}{(x+y)^2} = 7
& & \\
2x+\frac{1}{x+y}=3& &
\end{matrix}\right.$
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Mình sửa rồi đó
VIệt sửa sai đề của tớ rồi, hic
Edited by Giang1994, 23-03-2012 - 19:15.
$\LaTeX$
Edited by Giang1994, 23-03-2012 - 19:15.
$\LaTeX$
Don't let people know what you think
Edited by Dont Cry, 24-03-2012 - 22:40.
Giải hệ phương trình
$\left\{\begin{matrix}4xy + 4({x^2} + {y^2})+\frac{3}{(x+y)^2} = 7
& & \\
2x+\frac{1}{x+y}=3& &
\end{matrix}\right.$
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