Chứng minh rằng : $\frac{\sin x^{8}}{a^{3}} + \frac{\cos x^{8}}{b^{3}} = \frac{1}{(a + b)^{3}}$.
Edited by tramyvodoi, 18-01-2013 - 17:44.
$\frac{\sin x^{8}}{a^{3}} + \frac{\cos x^{8}}{b^{3}} = \frac{1}{(a + b)^{3}}$
Started By iloveyou123, 03-01-2013 - 11:06
#1
Posted 03-01-2013 - 11:06
iloveyou123
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Hạ sĩ
Biết rằng $\frac{\sin x^{4}}{a} + \frac{\cos x^{4}}{b} = \frac{1}{a + b}$.
Chứng minh rằng : $\frac{\sin x^{8}}{a^{3}} + \frac{\cos x^{8}}{b^{3}} = \frac{1}{(a + b)^{3}}$.
Chứng minh rằng : $\frac{\sin x^{8}}{a^{3}} + \frac{\cos x^{8}}{b^{3}} = \frac{1}{(a + b)^{3}}$.
#2
Posted 21-01-2013 - 18:49
Tran Hoai Nghia
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UNEXPECTED PLEASURE.
cho hỏi $\sin (x^{8})$ hay $(\sin x)^{8}$ vậy? 
SÁCH CHUYÊN TOÁN, LÝ , HÓA 
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