$a,\frac{x+1}{65}+\frac{x+3}{63}=\frac{x+5}{61}+\frac{x7}{59}$
$b,\frac{315-x}{101}+\frac{313-x}{103}+\frac{311-x}{105}+\frac{309-x}{107}+4=0$
$\large c,\frac{x-29}{1970}+\frac{x-27}{1972}+\frac{x-25}{1974}+\frac{x-23}{1976}+\frac{x-21}{1978}\frac{x-19}{1980}=\frac{x-1970}{29}+\frac{x-1972}{23}+\frac{x-1974}{25}+\frac{x-1976}{23}+\frac{x-1978}{21}+\frac{x-1980}{19}$
Phương trình ý C rất khó ai giải được thank luôn !
$b,\frac{315-x}{101}+\frac{313-x}{103}+\frac{311-x}{105}+\frac{309-x}{107}+4=0$
$\Longleftrightarrow$ $\frac{315-x}{101}+1+\frac{313-x}{103}+1+\frac{311-x}{105}+1+\frac{309-x}{107}+1=0$
$\Longleftrightarrow$ $\dfrac{416-x}{101} + \dfrac{416-x}{103} + \dfrac{416-x}{105} + \dfrac{416-x}{107}=0$
$\Longleftrightarrow$ $(416-x)A=0$
$\Longrightarrow$ $x=416$
$\cdot$ $( - 1) = {( - 1)^5} = {( - 1)^{2.\frac{5}{2}}} = {\left[ {{{( - 1)}^2}} \right]^{\frac{5}{2}}} = {1^{\frac{5}{2}}} =\sqrt{1}= 1$
$\cdot$ $\dfrac{0}{0}=\dfrac{100-100}{100-100}=\dfrac{10.10-10.10}{10.10-10.10}=\dfrac{10^2-10^2}{10(10-10)}=\dfrac{(10-10)(10+10)}{10(10-10)}=\dfrac{20}{10}=2$
$\cdot$ $\pi\approx 2^{5^{0,4}}-0,6-\left(\frac{0,3^{9}}{7}\right)^{0,8^{0,1}}$
$\cdot$ $ - 2 = \sqrt[3]{{ - 8}} = {( - 8)^{\frac{1}{3}}} = {( - 8)^{\frac{2}{6}}} = {\left[ {{{( - 8)}^2}} \right]^{\frac{1}{6}}} = {64^{\frac{1}{6}}} = \sqrt[6]{{64}} = 2$