Giải hệ phương trình
CodeCogsEqn (3).png 5.79K 141 Số lần tải
04-04-2015 - 22:37
28-03-2015 - 10:24
$\left ( y^2+2y+x^2 \right )y'+2x=0,y(1)=0$
04-08-2014 - 21:00
Giải phương trình:
1/ $ x^{3}-4x^{2}-5x+6=\sqrt[3]{7x^{2}+9x-4}$
2/ $16x^{3}-24x^{2}+12x-3=\sqrt[3]{x}$
3/ $3^{x}=1+x+\log _{3}^{1+2x}$
4/ $-2x^{3}+10x^{2}-17x+8=2x^{2}\sqrt[3]{5x-x^{3}}$
5/ $\left ( 5x-6 \right )^{2}-\frac{1}{\sqrt{5x-7}}=x^{2}-\frac{1}{\sqrt{x-1}}$
6/ $x^{3}+3x^{2}+4x+2=\left ( 3x+2 \right )\sqrt{3x+1}$
7/ $2\sqrt[3]{2x-1}=27x^{3}-27x^{2}+13x-2$
8/ $4x^{2}+2\sqrt{3-4x}-7=-\left ( \frac{5-4x^{2}}{2} \right )^{2}$
26-07-2014 - 00:41
vd1:
$x^{2}-4x+3=\sqrt{x+5}$
$x=\sqrt[3]{\frac{1}{54}\left ( -61+3\sqrt{417} \right )}-\frac{2}{9\sqrt[3]{\frac{1}{54}(-61+3\sqrt{417})}}+\frac{4}{3}$
26-07-2014 - 00:35
vd2:
$x^{4}-4x=1$
$x=\tan \left [ \frac{\pm\arccos \left ( \frac{2-\sqrt{2}}{2} \right ) }{2} \right ]+\frac{\Pi }{16}$
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