f3(x)=x^2014+x^1006+1=x^2014-x^2+x^1006-x+x^2+x+1=x^2(x^2012-1)+x(x^1005-1)+(x^2+x+1)
Ta thấy:
- x^2(x^2012-1)$\vdots$x^3-1=(x-1)(x^2+x+1)$\vdots$x^2+x+1
-x(x^1005-1)$\vdots$x^3-1=(x-1)(x^2+x+1)$\vdots$x^2+x+1
-x^2+x+1$\vdots$x^2+x+1
$\Rightarrow$ f3(x)$\vdots$x^
bài anh hahahano1
- Khanh 6c Hoang Liet yêu thích