Chứng minh rằng:
$a)$ $\mid a \mid\ \leq\ 1,\ \mid b \mid\ \leq\ 1$ thì $\mid a+b \mid\ <\ \mid 1+ab \mid$
$b)$ $\mid x \mid\ + \mid y \mid\ + \mid z \mid\ \leq\ \mid x+y-z \mid + \mid y+z-x \mid + \mid z+x-y \mid$
$c)$ $x^2+4y^2=1$ thì $\mid x+y \mid\ \leq\ \frac{\sqrt{5}}{2}$