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Posted by myduyen9a on 21-04-2013 - 05:32
$\sqrt{x+1}=t\geqslant 0\Rightarrow \sqrt{t^{2}-4t+4}+\sqrt{t^{2}-2t+1}=1 \Leftrightarrow \left | t-2 \right |+\left | t-1 \right |=1$
sau do ban xet dieu kien de tim duoc t