$\left\{\begin{matrix}
xy^{2}(\sqrt{x^{2}+1}+1) &=3.\sqrt{y^{2}+9}+3y & \\
(3x-1)\sqrt{x^{2}y+xy-5} &= 4x^{3}-3x^{3}y+7x &
\end{matrix}\right.$
18-03-2015 - 18:33
$\left\{\begin{matrix}
xy^{2}(\sqrt{x^{2}+1}+1) &=3.\sqrt{y^{2}+9}+3y & \\
(3x-1)\sqrt{x^{2}y+xy-5} &= 4x^{3}-3x^{3}y+7x &
\end{matrix}\right.$
18-03-2015 - 18:28
$$\left\{\begin{matrix}
x^{3} y^{3}\sqrt{3-x}+2y^{2}=4y^{3}\sqrt{3-x}-8 & \\
3y^{2}+2x-\sqrt{3-x}+\sqrt{2y-1}=0 &
\end{matrix}\right.$$
18-03-2015 - 18:27
Giải hệ phương trình: $$\left\{\begin{matrix}
x^{3} y^{3}\sqrt{3-x}+2y^{2}=4y^{3}\sqrt{3-x}-8 & \\
3y^{2}+2x-\sqrt{3-x}+\sqrt{2y-1}=0 &
\end{matrix}\right.$$
16-03-2015 - 20:47
Giải hệ phương trình này dùm mình nha
$$$x^{3}y^{3}\sqrt{3-x}+2y^{2}=4y^{3}\sqrt{3-x}-8$
3y^{2}+2x-\sqrt{3-x}+\sqrt{2y-1}=0$
12-10-2014 - 10:44
$x^{log{_{6}}^{3x}} - 36\sqrt[{5}]{x^{7}}=0$
$\frac{3}{2^{x}+\sqrt{1+log_{2}}x}=1$
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