viendanho98

$\sqrt{2x^3+4x^2+4x}-\sqrt[3]{16x^3+12x^2+6x-3} \geq 4x^4+2x^3-2x-1$

$\sqrt{x^2+(1-\sqrt{3})x+2} +\sqrt{x^2+(1+\sqrt{3})x+2}\leq 3\sqrt{2}-\sqrt{x^2-2x+2}$

giải pt ;$x^2-4x+2=\sqrt{x+2}$

$x^2-x-1000\sqrt{1+8000x}=1000$

$3(2+\sqrt{x-2})=2x+\sqrt{x+6}$