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bsxilytol

bsxilytol

Đăng ký: 18-06-2013
Offline Đăng nhập: 08-05-2014 - 15:33
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#447517 $4x^{2}+14x+11=4\sqrt{6x+10}$

Gửi bởi bsxilytol trong 03-09-2013 - 14:12

1.$\sqrt{3x+4} - \sqrt{5-x} + 3x^{2} -8x-19 > 0$

2.$\sqrt{x-\frac{1}{x}}+\sqrt{x^{2}-x}=2$

3.$4x^{2}+14x+11=4\sqrt{6x+10}$

4.$4\left ( 2x^{2}+1 \right )+3\left ( x^{2}-2 \right )\sqrt{2x-1}=2\left ( x^{3}+5x \right )$

5.$\frac{\left ( 2x-1 \right )\sqrt{x+3}}{2\sqrt{x}+\left ( 2+\sqrt{x} \right )\sqrt{1-x}+1-x}\geqslant 1$