Kaito Kuroba

p/s: x,y,z>0

Nguồn: Facebook

P/s : Nguồn : https://www.facebook...&type=1

$\left\{\begin{matrix}\sqrt[5]{4x^5+y^5}+\sqrt[4]{3x^4+2y^4}+\sqrt[3]{2x^3+3y^3}+\sqrt{x^2+4y^2}=\sqrt[6]{6}& \\ 2\sqrt[2013]{\frac{3x^6-12x^5y+30x^4y^2-40x^3y^3+30x^2y^4-12xy^5+2y^6}{-x^6+8x^5y-19x^4y^2+20x^3y^3-10x^2y^4+2xy^5}}=3\left(\frac{3x^2-4xy+2y^2}{y^2-x^2} \right)^{\frac{2014}{2015}}-1 & \end{matrix}\right.$

Giải hệ phương trinh sau:

$\left\{\begin{matrix}
 \left ( \sqrt[3]{15x^6-9y^4+7y^2-16x+4} \right )^{2013}+\left ( \sqrt[4]{20y^6-8x^2+7x^2-17y-2} \right )^{2014}= \left ( \sqrt[5]{5x^6+6x^5-4y^6-3y^3-3y-4+3}\right )^{2015} & \\
 9\left (x^{10}-10x^9+50x^8-160x^7+360x^6-592x^5+719x^4-636x^3+392x^2-152x+31  \right )\left ( 81x^5-270y^4+360y^3-243y^2+84y-11 \right )^2=x^6-6x^5+18x^4y+6x^4-72x^3y+16x^3+108x^2y^2-12x^2-216xy^2+144xy-24x+216y^3-21y^2+72y-8&
\end{matrix}\right.$

P/s: vì đề hơi dài, nên sẽ khó nhìn, mong mọi người thông cảm ạ!!!!!

$\left\{\begin{matrix} \sqrt[4]{3y^6-2y^5+y^4+x^6+x^5-3y^4}+\sqrt[3]{4x^2-2y^2+6xy^2}=3 & \\ x^3(2y-x)(x^2+y^2)=6x^3y-3x^4-1& \end{matrix}\right.$