Ta có: $\left\{\begin{matrix} f(1)=a+b+c\\f(0)=c \\ f(-1)=a-b+c \end{matrix}\right.\Rightarrow \left\{\begin{matrix} a=\frac{f(1)+f(-1)-2f(0)}{2}\leq 2\\ c=f(0)<=1 \\ b=\frac{f(1)+f(-1)}{2}\leq 1 \end{matrix}\right.$
$ \Rightarrow |f(x)|\leq |2x^2 +x+1|\leq 2|x^2|+|x|+1\leq 7 \forall x, |x|\leq 2$
- canhhoang30011999, nhatmai và congdaoduy9a thích