$\left\{\begin{matrix} 6x^{4}-(x^{3}-x).y^{2}-(y+12)x^{2}= -6 & \\ & \\ 5x^{4}-(x^{2}-1).y^{2}-11x^{2}= -5 & \end{matrix}\right.$
Chú ý: Cách gõ công thức Toán.
19-04-2015 - 21:26
$\left\{\begin{matrix} 6x^{4}-(x^{3}-x).y^{2}-(y+12)x^{2}= -6 & \\ & \\ 5x^{4}-(x^{2}-1).y^{2}-11x^{2}= -5 & \end{matrix}\right.$
Chú ý: Cách gõ công thức Toán.
23-03-2015 - 21:24
$\left\{\begin{matrix} xy + x -2 = 0 & \\ & \\ 2x^{3}-x^{2}y+x^{2}+y^{2}- 2xy-y=0 & \end{matrix}\right.$
$\left\{\begin{matrix} 5x^{2}y^{2}-4xy^{2}+3y^{3}-2\left ( x+y \right )^{2}=0 & \\ & \\ xy(x^{2}+y^{2})+2= (x+y)^{2} & \end{matrix}\right.$
17-03-2015 - 21:12
1, $\left\{\begin{matrix} \sqrt{7x+y} + \sqrt{2x+y} = 5 & \\ & \\ \sqrt{2x+y} + x-y=2 & \end{matrix}\right.$
2, $\left\{\begin{matrix} \sqrt{x^{2}+6y}=y+3 & \\ & \\ \sqrt{2x+y}+x-y=4& \end{matrix}\right.$
3, $\left\{\begin{matrix} \sqrt{x+y}=9-\left | x+2y \right | & \\ & \\ x(x+4y-2)+y(4y+2)=41& \end{matrix}\right.$
23-02-2015 - 21:32
1, $\frac{2x}{\sqrt{2x+9}}< \sqrt{2x+1}-1$
2, $\sqrt{1-2x}+\sqrt{1+2x}\geq 2-x^{2}$
3, $\frac{1}{1-x^{2}}+1> \frac{3x}{\sqrt{1-x^{2}}}$
23-02-2015 - 21:20
$\left\{\begin{matrix} x^{3}-y^{3}=35 & \\ & \\ 2x^{2}+3y^{2}=4x-9y& \end{matrix}\right.$
Community Forum Software by IP.Board
Licensed to: Diễn đàn Toán học