bài 5, a,b,c$\geq$0 $a+b+c=1$ Tìm Min $P=\sqrt{a^{3}+3a+0.5}+\sqrt{b^{3}+3b+0.5}+\sqrt{c^{3}+3c+0.5}$
bài 6. a,b,c$\geq$0 $a+b+c=1$ CMR $10(a^{3}+b^{3}+c^{3})-9\left ( a^{5}+b^{5}+c^{5} \right )\geq 1$
26-07-2015 - 09:23
bài 5, a,b,c$\geq$0 $a+b+c=1$ Tìm Min $P=\sqrt{a^{3}+3a+0.5}+\sqrt{b^{3}+3b+0.5}+\sqrt{c^{3}+3c+0.5}$
bài 6. a,b,c$\geq$0 $a+b+c=1$ CMR $10(a^{3}+b^{3}+c^{3})-9\left ( a^{5}+b^{5}+c^{5} \right )\geq 1$
25-07-2015 - 22:24
còn vài phút à ace chém hộ !!!
15-07-2015 - 23:50
$a,b,c\geq 0 ,ab+bc+ca>0. CMR\sum \sqrt{1+\frac{48a}{b+c}}\geq 15$
15-07-2015 - 23:47
$a,b,c>0 CMR \sum \sqrt{\frac{a^{2}}{a^{2}+7ab+b^{2}}}\geq 1$
15-07-2015 - 04:58
Cho các số dương $a,b,c,d$ có tổng bằng $4$ . Chứng minh rằng
$\sum \frac{a+1}{b^{2}+1} \geq 4$
$\sum \left ( \frac{a+1}{b^{2}+1} \right )= \sum \left ( a+1-\frac{ b^{2}( a+1 )}{b^{2}+1} \right )\geq \sum (a+1-\frac{b(a+1)}{2})\geq 2$
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