dkhoan

nhưng mà toàn bài khó à

ừ toàn bài về nhà của mình đấy

Sao nhìu thế!

dạo này mình thừa hpt

1.$\left\{\begin{matrix} 2x^{4}-2x^{2}y+2x^{2}+x^{2}y^{2}=33 & & \\ x^{4}-y^{2}+2y=6 & & \end{matrix}\right.$

2.$\left\{\begin{matrix} 6x^{2}+6xy-9x+1=0 & & \\84x^{4}+12x^{2}y-12x^{3}y^{2}-21x^{2}+1=0 & & \end{matrix}\right.$

3.$\left\{\begin{matrix} x^{3}+x^{2} (y-2)-2=0& & \\x(x+y)+y^{2}-4y+1=0 & & \end{matrix}\right.$

4.$\left\{\begin{matrix} (xy+x^{2})^{2}+(x+y)^{2}=8y^{2}+x^{3}y-1 & & \\ x^{6}+1+x^{3}y^{3}+3xy(xy+1)=9y^{3} & & \end{matrix}\right.$

5.$\left\{\begin{matrix} (1-y)(4x-1)+xy+3x^{2}-2y^{2}=4 & & \\13x^{2}+3y^{2}-11xy=7 & & \end{matrix}\right.$

6.$\left\{\begin{matrix} \frac{1}{y}+2x=\frac{6}{y^{2}} & & \\ \frac{2y^{4}}{x}+\frac{5y^{2}}{x}-\frac{1}{x}=4y(xy+1) & & \end{matrix}\right.$

7.$\left\{\begin{matrix} 3xy\sqrt{xy}-(3x-2y)^{3}=2 & & \\3x(\sqrt{xy}+3x)+2y(2y-\sqrt{xy})=\frac{2}{\sqrt{xy}}+12xy & & \end{matrix}\right.$

8.$\left\{\begin{matrix} 6x+3y=4xy^{2}(1+x)+3y^{2} & & \\12xy(x+y)+(y-1)^{3}+y(2y+3)(y-1)=0 & & \end{matrix}\right.$

9.$\left\{\begin{matrix} x+\frac{1}{y}+\sqrt{x}+\frac{1}{y\sqrt{x}}-\frac{1}{\sqrt{x}}=-1 & & \\xy(x+1)+\frac{1}{y}+2x=y & & \end{matrix}\right.$

10.$\left\{\begin{matrix} (x+1)^{2}(x^{2}+y)+(x+1)(\frac{x+1}{y+1}-2)+1=0 & & \\(y+1)^{2}(y^{2}+x)+(y+1)(\frac{y+1}{x+1}-2)+1=0 & & \end{matrix}\right.$

11.$\left\{\begin{matrix} (x^{2}-y)^{2}(y-2)+x^{2}y-y^{2}-2x^{2}+y=1 & & \\x^{2}-2y+2=0 & & \end{matrix}\right.$

1.$\left\{\begin{matrix} \sqrt{2x^{2}+y-1}-x^{4}y^{2}+6x^{2}y=9 & & \\ \sqrt{x^{2}y-3}+4x^{2}(1-x^{2}-y)+2y-y^{2}=1 & & \end{matrix}\right.$

2.$\left\{\begin{matrix} 6\sqrt{5+x^{2}-2x}+3\sqrt{2x-x^{2}}=0 & & \\ x^{4}y^{4}-2x^{2}y^{2}-x+18=0 & & \end{matrix}\right.$

3.$\left\{\begin{matrix} \sqrt{4x+10y}-\sqrt{2x+2y}=4 & & \\x+2y+\frac{2\sqrt{2x^{2}+7xy+5y^{2}} }{3}=24 & & \end{matrix}\right.$

4.$\left\{\begin{matrix} x^{2}-1+2\sqrt[3]{x^{2}-1}-\sqrt[3]{y^{2}}=0 & & \\ (x+y)^{2}+1=2(1+xy)-(\sqrt[3]{x^{2}-1}+\sqrt[3]{y^{2}}) & & \end{matrix}\right.$

5.$\left\{\begin{matrix} \sqrt{(\frac{x}{y})^{3}}+\frac{x}{y}+x\sqrt{\frac{x}{y}}+x=4 & & \\ \sqrt{\frac{x}{y}}=\frac{2}{y+1} & & \end{matrix}\right.$

6.$\left\{\begin{matrix} x+\sqrt{x^{2}-x}-\sqrt{y}+\sqrt{xy-y}+\sqrt{xy}=\sqrt{x} & & \\(2x-1+\frac{y}{x}+2\sqrt{x^{2}-x})(\sqrt{x}-\sqrt{\frac{y}{x}}+\sqrt{x-1})=1 & & \end{matrix}\right.$

7.$\left\{\begin{matrix} \frac{3}{\sqrt[3]{2x+y}}+\frac{2}{\sqrt[3]{3x+8y}}=4 & & \\ (x+7y)^{2}-(5x+2y)^{3}=41 & & \end{matrix}\right.$

8.$\left\{\begin{matrix} \frac{\sqrt{x^{3}+x^{2}y^{2}}}{xy^{2}}-\frac{\sqrt{x}}{y^{2}}+\frac{1}{2\sqrt{x+y^{2}}-\sqrt{x}}=2 & & \\ 3\sqrt{x+y^{2}}-2\sqrt{x+2y^{2}+\sqrt{x^{2}+xy^{2}}}=0 & & \end{matrix}\right.$

9.$\left\{\begin{matrix} (x+1)(xy-y^{2}+y-1)=3y & & \\ y^{2}(2x-y)(2x-y-4)+(2y+1)^{2}=4xy-2y^{2} & & \end{matrix}\right.$

   Ngại gì không thử,yêu cầu ghi rõ cách giải:

     1. $x^3+6x+2=2\sqrt{x^{2}(5x-1)}+\sqrt[3]{6x^{2}+x+1}+\sqrt{4x^{3}+4x^{2}+1}$

     2. $x^{2}-5x+5=(x-1)\sqrt{3(x^{2}-8x+11)}$

     3. $x^{2}+1=(x^{2}-x-1)\sqrt{2x^{2}-3x+5}$         

     4. $x^{2}-9x+5+x\sqrt{2x^{2}+6}=\sqrt{6x-1}$

     5. $4x^{2}+5x+5=(2x+3)\sqrt{3x^{2}+2x+3}$

     6. $(\sqrt{x-2}+1)^{3}=\sqrt{x^{3}+3x^{2}+10}$

     7. $(\sqrt{1+x}+1)^{3}=\sqrt{x^{3}+2}$

     8. $2\sqrt{x^{2}+x+1}+\sqrt{x^{2}+3x+8}=3x+4$   

     9. $\frac{\sqrt{x-2}}{\sqrt{2x+1}-1}=\frac{1}{\sqrt{x+4}-\sqrt{x-2}}$

    10.$\sqrt{x-1}\sqrt[3]{3x+2}+(x^{2}+1)\sqrt{2x+5}-2x^{2}-3x-3=0$

    11.$(x^{3}+1\)(\sqrt[3]{2(x+1)})+(x^{2}+2)\sqrt{x-2}=7x^{2}-x+7$

    12.$3\sqrt[3]{x}+\sqrt{x^{2}+8}-2=\sqrt{x^{2}+15}$

    13.$\sqrt{x+2}+\sqrt{5x+6}+2\sqrt{8x+9}=4x^{2}$

    14.$\sqrt[3]{7x-8}+\sqrt{\frac{7-2x^{2}}{6}}=x$                                                                      

chia cả 2 vế cho x rồi đặt ẩn phụ