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giải hệ phương trình$\left\{\begin{matrix} x^{2} +y^{2}&-y\left ( 4-x \right )=-1 \\ \left ( 1+x^{2} \right )^{2}+y^{2}\left ( 2x+2y-7 \right ) & =0 \end{matrix}\right.$
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hiroshima
#637728 $\left\{\begin{matrix} x^{2} +y^{2}&-y\left ( 4-...
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on 03-06-2016 - 06:01
