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26-12-2016 - 21:08
CodeCogsEqn (2).gif 5.8KB 113 downloads
Lại có $\frac{1}{x}+\frac{1}{y}+\frac{1}{z}\geq \frac{9}{x+y+z}$
Mà $\frac{1}{x}+\frac{1}{y}+\frac{1}{z}\leq 3$
suy ra $x+y+z\geq 3$
Vậy min P =$\frac{3}{4}$ khi x=y=z=1
25-12-2016 - 19:37
duy.png 138.86KB 42 downloads
23-12-2016 - 22:43
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15-12-2016 - 19:38
Đây bạn
12-12-2016 - 19:03
bdt.png 144.4KB 43 downloads