$tan\angle AFD=\frac{AD}{DF}=\frac{1}{2}\Leftrightarrow \angle AFD\approx 26^{\circ}34{}'.$
$tan\angle ACD=\frac{AD}{CD}=\frac{1}{3}\Leftrightarrow \angle ACD\approx 18^{\circ}26'.$
$\Rightarrow \angle AFD+\angle ACD=45^{\circ}.$
Mình chỉ biết làm như vậy.