luonghien12903

giải phương trình sau:

$2\sqrt{\frac{x^2+x+1}{x+4}}+x^2-4=\frac{2}{\sqrt{x^2+1}}$

1) $x\sqrt{x+\sqrt{x}}-\sqrt{x-\sqrt{x}}=\frac{3}{2}\sqrt{\frac{x}{x+\sqrt{x}}}$

2)$\sqrt[5]{\frac{16x}{x-1}}+\sqrt[5]{\frac{x-1}{16x}}=25$

3)$\sqrt{x}+\sqrt{x+7}+2\sqrt{x^2+7x}=35-2x$

4)$\sqrt[4]{(x-1)^2}-\sqrt[4]{(x+1)^2}=\frac{3}{2}\sqrt[4]{x^2-1}$

5)$x^3+6x^2+12x=2\sqrt[3]{4x+3}+9$