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supreme king

supreme king

Đăng ký: 27-06-2019
Offline Đăng nhập: 08-08-2019 - 09:52
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$x+y+z\leq 4$

05-08-2019 - 15:08

Cho x,y,z thõa mãn

 

$x\left ( x-1 \right )+y\left ( y-1 \right )+z\left ( z-1 \right )\leq \frac{4}{3}$

  

Chứng minh rằng

 

$x+y+z\leq 4$


$\frac{1}{\sqrt{2}}\leq x^{3...

04-08-2019 - 15:22

Cho$x,y\geq 0$ và$x^{2}+y^{2}\doteq 1$. Chứng minh rằng

 

$\frac{1}{\sqrt{2}}\leq x^{3}+y^{3}\leq 1$


$\frac{1}{a}+...\geq\frac{2a+b}{...

04-08-2019 - 15:18

Cho a, b, c là các số thực dương. Chứng minh rằng

 

$\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\geq \frac{2a+b}{a\left ( a+2b \right )}+\frac{2b+c}{b\left ( b+2c \right )}+\frac{2c+a}{c\left ( c+2a \right )}$


$a^{3}b^{2}+b^{3}c^{2}+c^{3}a^...

20-07-2019 - 14:30

Cho $a> b> c> 0$. Chứng minh rằng

 

$a^{3}b^{2}+b^{3}c^{2}+c^{3}a^{2}> a^{2}b^{3}+b^{2}c^{3}+c^{2}a^{3}$


$\frac{\left ( a+b \right )\left ( 1-ab \right )...

18-07-2019 - 18:52

Cmr:

$-\frac{1}{2}\leq \frac{\left ( a+b \right )\left ( 1-ab \right )}{\left ( 1+a^{2} \right )\left ( 1+b^{2} \right )}\leq \frac{1}{2}$