Cho $a\geq 1,b\geq 1$
Chứng minh rằng: $a\sqrt{b-1}+b\sqrt{a-1}\leq ab$
Edited by chanyeoll, 04-12-2015 - 03:52.
Cho $a\geq 1,b\geq 1$
Chứng minh rằng: $a\sqrt{b-1}+b\sqrt{a-1}\leq ab$
Edited by chanyeoll, 04-12-2015 - 03:52.
Cho $a\geq 1,b\geq 1$
Chứng minh rằng: $a\sqrt{b-1}+b\sqrt{a-1}\leq ab$
Bài nãy đã có ở đây: http://diendantoanho...sqrta-1-leq-ab/
0 members, 1 guests, 0 anonymous users