$$a^2$$
#41
Đã gửi 23-04-2017 - 23:04
#42
Đã gửi 27-04-2017 - 22:50
$\begin{tikzpicture}[line cap=round,line join=round,>=triangle 45,x=1.0cm,y=1.0cm] \clip(4.22,-2.86) rectangle (13.12,4.98); \draw(8.34,0.2) circle (2.330321866180721cm); \draw (6.86,-1.6)-- (9.827822560606734,-1.5935395251149667); \draw (8.334927274150267,2.5303163449309705)-- (6.86,-1.6); \draw (8.334927274150267,2.5303163449309705)-- (9.827822560606734,-1.5935395251149667); \draw (8.334927274150267,2.5303163449309705)-- (8.345072725849732,-2.1303163449309706); \draw (6.035459992649993,-0.1456810011025011)-- (8.345072725849732,-2.1303163449309706); \draw [domain=4.22:13.12] plot(\x,{(-17.62190491273828--2.3096127331997396*\x)/1.9846353438284694}); \draw (7.290242190121254,-0.3951701881975841)-- (7.725725721359615,-1.5981154536142386); \draw (8.770410805388625,1.327371079514322)-- (7.725725721359615,-1.5981154536142386); \draw(7.290242190121254,-0.3951701881975841) circle (1.2793448391923807cm); \draw(8.770410805388625,1.327371079514322) circle (3.1064188996832454cm); \draw (6.035459992649993,-0.1456810011025011)-- (6.86,-1.6); \draw (6.86,-1.6)-- (8.345072725849732,-2.1303163449309706); \draw (8.345072725849732,-2.1303163449309706)-- (9.827822560606734,-1.5935395251149667); \draw (6.035459992649993,-0.1456810011025011)-- (9.827822560606734,-1.5935395251149667); \begin{normalsize} \draw [fill=white] (8.34,0.2) circle (1.5pt); \draw[color=black] (8.44,0.41) node {$O$}; \draw [fill=white] (6.86,-1.6) circle (1.5pt); \draw[color=black] (6.68,-1.63) node {$B$}; \draw [fill=white] (9.827822560606734,-1.5935395251149667) circle (1.5pt); \draw[color=black] (9.92,-1.67) node {$C$}; \draw [fill=white] (8.334927274150267,2.5303163449309705) circle (1.5pt); \draw[color=black] (8.4,2.83) node {$A$}; \draw [fill=white] (8.345072725849732,-2.1303163449309706) circle (1.5pt); \draw[color=black] (8.36,-2.23) node {$K$}; \draw [fill=white] (6.035459992649993,-0.1456810011025011) circle (1.5pt); \draw[color=black] (5.94,0.07) node {$I$}; \draw [fill=white] (7.725725721359615,-1.5981154536142386) circle (1.5pt); \draw[color=black] (7.78,-1.35) node {$M$}; \draw [fill=white] (6.880592857004804,-0.8718982273583699) circle (1.5pt); \draw [fill=white] (7.290242190121254,-0.3951701881975841) circle (1.5pt); \draw[color=black] (7.12,-0.25) node {$D$}; \draw [fill=white] (8.770410805388625,1.327371079514322) circle (1.5pt); \draw[color=black] (8.96,1.37) node {$E$}; \end{normalsize} \end{tikzpicture}$
Bài viết đã được chỉnh sửa nội dung bởi Mr Cooper: 27-04-2017 - 22:50
#43
Đã gửi 30-04-2017 - 10:23
$a/b$$\frac{2x+3}{3x}}$
$\lim_{x\to\infty}\frac{2x}{3x+5}$
$\sum _{k=1}^n\frac{1}{2\sqrt{x+2}}$
$(\sqrt{2}+1)\left ( \sqrt{3} \right +1)\left ( \sqrt{6} \right +1)\left ( 5-2\sqrt{2} \right -\sqrt{3})$
#44
Đã gửi 02-05-2017 - 21:38
\[\left\{\begin{matrix} x^3-y^3+6x^2-3y^2=-12x+3y-7\\ y\sqrt{x+3}+(y+6)\sqrt{x+10}=y^2+4x \end{matrix}\right.\]
#45
Đã gửi 04-05-2017 - 14:25
.
Bài viết đã được chỉnh sửa nội dung bởi Haru Atsuko: 04-05-2017 - 14:26
#46
Đã gửi 07-05-2017 - 09:30
$\sqrt[5]{6}\int_{4}^{6}$ $\int_{2}^{6}$ $n \to 3\int_{2}^6{}$
#47
Đã gửi 12-05-2017 - 07:47
$\begin{tikzpicture}[line cap=round,line join=round,>=triangle 45,x=1.0cm,y=1.0cm] \clip(4.22,-2.86) rectangle (13.12,4.98); \draw(8.34,0.2) circle (2.330321866180721cm); \draw (6.86,-1.6)-- (9.827822560606734,-1.5935395251149667); \draw (8.334927274150267,2.5303163449309705)-- (6.86,-1.6); \draw (8.334927274150267,2.5303163449309705)-- (9.827822560606734,-1.5935395251149667); \draw (8.334927274150267,2.5303163449309705)-- (8.345072725849732,-2.1303163449309706); \draw (6.035459992649993,-0.1456810011025011)-- (8.345072725849732,-2.1303163449309706); \draw [domain=4.22:13.12] plot(\x,{(-17.62190491273828--2.3096127331997396*\x)/1.9846353438284694}); \draw (7.290242190121254,-0.3951701881975841)-- (7.725725721359615,-1.5981154536142386); \draw (8.770410805388625,1.327371079514322)-- (7.725725721359615,-1.5981154536142386); \draw(7.290242190121254,-0.3951701881975841) circle (1.2793448391923807cm); \draw(8.770410805388625,1.327371079514322) circle (3.1064188996832454cm); \draw (6.035459992649993,-0.1456810011025011)-- (6.86,-1.6); \draw (6.86,-1.6)-- (8.345072725849732,-2.1303163449309706); \draw (8.345072725849732,-2.1303163449309706)-- (9.827822560606734,-1.5935395251149667); \draw (6.035459992649993,-0.1456810011025011)-- (9.827822560606734,-1.5935395251149667); \begin{normalsize} \draw [fill=white] (8.34,0.2) circle (1.5pt); \draw[color=black] (8.44,0.41) node {$O$}; \draw [fill=white] (6.86,-1.6) circle (1.5pt); \draw[color=black] (6.68,-1.63) node {$B$}; \draw [fill=white] (9.827822560606734,-1.5935395251149667) circle (1.5pt); \draw[color=black] (9.92,-1.67) node {$C$}; \draw [fill=white] (8.334927274150267,2.5303163449309705) circle (1.5pt); \draw[color=black] (8.4,2.83) node {$A$}; \draw [fill=white] (8.345072725849732,-2.1303163449309706) circle (1.5pt); \draw[color=black] (8.36,-2.23) node {$K$}; \draw [fill=white] (6.035459992649993,-0.1456810011025011) circle (1.5pt); \draw[color=black] (5.94,0.07) node {$I$}; \draw [fill=white] (7.725725721359615,-1.5981154536142386) circle (1.5pt); \draw[color=black] (7.78,-1.35) node {$M$}; \draw [fill=white] (6.880592857004804,-0.8718982273583699) circle (1.5pt); \draw [fill=white] (7.290242190121254,-0.3951701881975841) circle (1.5pt); \draw[color=black] (7.12,-0.25) node {$D$}; \draw [fill=white] (8.770410805388625,1.327371079514322) circle (1.5pt); \draw[color=black] (8.96,1.37) node {$E$}; \end{normalsize} \end{tikzpicture}$
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- Mr Cooper yêu thích
Discovery is a child’s privilege. I mean the small child, the child who is not afraid to be wrong, to look silly, to not be serious, and to act differently from everyone else. He is also not afraid that the things he is interested in are in bad taste or turn out to be different from his expectations, from what they should be, or rather he is not afraid of what they actually are. He ignores the silent and flawless consensus that is part of the air we breathe – the consensus of all the people who are, or are reputed to be, reasonable.
Grothendieck, Récoltes et Semailles (“Crops and Seeds”).
#48
Đã gửi 12-05-2017 - 15:34
[latex]
[+preamble]
\usepackage{tikz}
[/preamble]
\begin{tikzpicture}[scale=2]
\shade[top color=blue,bottom color=gray!50]
(0,0) parabola (1.5,2.25) |- (0,0);
\draw (1.05cm,2pt) node[above]
{$\displaystyle\int_0^{3/2} \!\!x^2\mathrm{d}x$};
\draw[style=help lines] (0,0) grid (3.9,3.9)
[step=0.25cm] (1,2) grid +(1,1);
\draw[->] (-0.2,0) -- (4,0) node[right] {$x$};
\draw[->] (0,-0.2) -- (0,4) node[above] {$f(x)$};
\foreach \x/\xtext in {1/1, 1.5/1\frac{1}{2}, 2/2, 3/3}
\draw[shift={(\x,0)}] (0pt,2pt) -- (0pt,-2pt) node[below] {$\xtext$};
\foreach \y/\ytext in {1/1, 2/2, 2.25/2\frac{1}{4}, 3/3}
\draw[shift={(0,\y)}] (2pt,0pt) -- (-2pt,0pt) node[left] {$\ytext$};
\draw (-.5,.25) parabola bend (0,0) (2,4) node[below right] {$x^2$};
\end{tikzpicture}
[/latex]
#49
Đã gửi 12-05-2017 - 15:35
*** Cannot compile formula: \begin{tikzpicture}[scale=2]\shade[top color=blue,bottom color=gray!50](0,0) parabola (1.5,2.25) |- (0,0);\draw (1.05cm,2pt) node[above]{$\displaystyle\int_0^{3/2} \!\!x^2\mathrm{d}x$};\draw[style=help lines] (0,0) grid (3.9,3.9)[step=0.25cm] (1,2) grid +(1,1);\draw[->] (-0.2,0) -- (4,0) node[right] {$x$};\draw[->] (0,-0.2) -- (0,4) node[above] {$f(x)$};\foreach \x/\xtext in {1/1, 1.5/1\frac{1}{2}, 2/2, 3/3}\draw[shift={(\x,0)}] (0pt,2pt) -- (0pt,-2pt) node[below] {$\xtext$};\foreach \y/\ytext in {1/1, 2/2, 2.25/2\frac{1}{4}, 3/3}\draw[shift={(0,\y)}] (2pt,0pt) -- (-2pt,0pt) node[left] {$\ytext$};\draw (-.5,.25) parabola bend (0,0) (2,4) node[below right] {$x^2$};\end{tikzpicture} *** Error message: Error: Nothing to show, formula is empty
#50
Đã gửi 12-05-2017 - 22:43
$0\leq m\leq \frac{6}{5}, m\neq 1$
#51
Đã gửi 26-05-2017 - 13:10
#52
Đã gửi 26-05-2017 - 13:13
#53
Đã gửi 26-05-2017 - 13:16
Tìm GTLN của P=$\frac{x.y}{(x+y)^2}$
Bài viết đã được chỉnh sửa nội dung bởi Phongkute: 26-05-2017 - 13:20
#54
Đã gửi 02-06-2017 - 17:40
$^{^{a}}$
#55
Đã gửi 02-06-2017 - 17:41
$^{\frac{1}{3}}$
Bài viết đã được chỉnh sửa nội dung bởi linhk2: 03-06-2017 - 10:53
#56
Đã gửi 03-06-2017 - 10:52
$\frac{a^{2}}{b+c}$
Bài viết đã được chỉnh sửa nội dung bởi linhk2: 03-06-2017 - 10:52
#57
Đã gửi 09-06-2017 - 13:16
$\fn_phv \frac{1}{1+\frac{b}{a}}^{2}$
#58
Đã gửi 09-06-2017 - 13:26
#59
Đã gửi 09-06-2017 - 23:20
lỡ tắt latex rồi thì sao ạ? Em loay hoay mãi...
#60
Đã gửi 20-07-2017 - 17:47
$\sqrt{a+b^2}$
Bài viết đã được chỉnh sửa nội dung bởi shiroyuki10112002: 20-07-2017 - 17:50
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